Find the probability of obtaining exactly six heads in ten tosses of a fair coin.
A) $10 !\left(\frac{1}{2}\right)^{10}$
B) $\left(\frac{1}{2}\right)^{6}$
C) $151,200\left(\frac{1}{2}\right)^{10}$
D) $6 !\left(\frac{1}{2}\right)^{6}$
E) $210\left(\frac{1}{2}\right)^{10}$

Question

Quizplus · Accepted Answer

The correct answer is obtained by calculating the number of ways to choose 6 heads out of 10 tosses, which is $\binom{10}{6}$, and then multiplying by the probability of each of those outcomes, which is $\left(\frac{1}{2}\right)^{10}$. The calculation $\binom{10}{6} = 210$ leads to the correct answer, $210\left(\frac{1}{2}\right)^{10}$.

Find the Probability of Obtaining Exactly Six Heads in Ten 10!(12)1010 !\left(\frac{1}{2}\right)^{10}10!(21​)10

Find the Probability of Obtaining Exactly Six Heads in Ten $10 !\left(\frac{1}{2}\right)^{10}$