Find the variance for the given data. Round your answer to one more decimal place than the original data. To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices he was quoted are listed below: $\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$
A) $36,838.2$ dollars 2
B) $36,838.3$ dollars 2
C) $30,698.6$ dollars $^ { 2 }$
D) $1,207,582.7$ dollars $^ { 2 }$

Question

Quizplus · Accepted Answer

The variance is calculated as the average of the squared differences from the mean. The mean of the data is $402.5. The squared differences from the mean are:$\begin{array} { l l l l l l } (663 - 402.5)^2 = 167,225 & (273 - 402.5)^2 = 168,062.5 & (410 - 402.5)^2 = 56.25 & (622 - 402.5)^2 = 46,656.25 & (174 - 402.5)^2 = 51,980.25 & (374 - 402.5)^2 = 7,849 \end{array}$The sum of the squared differences is 518,829.25. The variance is 518,829.25 / 6 = 86,471.54. Rounding to one more decimal place, the variance is $86,471.5.

Find the Variance for the Given Data $663$273$410$622$174$374\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$663​$273​$410​$622​$174​$374​

Find the Variance for the Given Data $\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$