Determine the center of the ellipse.
-$$\frac { ( \mathrm { x } + 5 ) ^ { 2 } } { 9 } + \frac { ( \mathrm { y } - 5 ) ^ { 2 } } { 25 } = 1$$
A) (-5,-5)
B)(,5)
C) (,-5)
D) (-5,5)

Question

Quizplus · Accepted Answer

The center of an ellipse in the form $\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1$ is at the point (h, k). For the given ellipse, $h = -5$ and $k = 5$, so the center is (-5, 5).

Determine the Center of the Ellipse (x+5)29+(y−5)225=1\frac { ( \mathrm { x } + 5 ) ^ { 2 } } { 9 } + \frac { ( \mathrm { y } - 5 ) ^ { 2 } } { 25 } = 19(x+5)2​+25(y−5)2​=1

Determine the Center of the Ellipse $\frac { ( \mathrm { x } + 5 ) ^ { 2 } } { 9 } + \frac { ( \mathrm { y } - 5 ) ^ { 2 } } { 25 } = 1$