Solve for x.
-$$2 ^ { 3 x + 7 } = \frac { 1 } { 4 }$$
A) $x = 1$
B) $x = \frac { 1 } { 2 }$
C) $x = - 3$
D) $x = 3$

Question

Quizplus · Accepted Answer

First, express $\frac{1}{4}$ as $2^{-2}$ to have the same base on both sides of the equation: $2^{3x+7} = 2^{-2}$. Then, set the exponents equal to each other because if $a^m = a^n$, then $m = n$. So, $3x + 7 = -2$. Solving for $x$, subtract 7 from both sides to get $3x = -9$, and then divide by 3 to find $x = -3$.

Solve for X 23x+7=142 ^ { 3 x + 7 } = \frac { 1 } { 4 }23x+7=41​

Solve for X $2 ^ { 3 x + 7 } = \frac { 1 } { 4 }$