Solve the system of equations.
-$$\begin{array} { r l r }
x - y + 5 z & = & - 4 \
3 x + z & = & 0 \
- x + y - 5 z & = & 12
\end{array}$$
A) $( 0,0,4 )$
B) $( 5,4,0 )$
C) No solution
D) Infinite number of solutions; dependent equations

Question

Solve the system of equations.
-$$\begin{array} { r l r } 
x - y + 5 z & = & - 4 \
3 x + z & = & 0 \
- x + y - 5 z & = & 12
\end{array}$$
A) $( 0,0,4 )$
B) $( 5,4,0 )$
C) No solution
D) Infinite number of solutions; dependent equations

Quizplus · Accepted Answer

Adding the first and third equations cancels out $y$ and $z$, resulting in $0 = 8$, which is a contradiction. This indicates that the system has no solution.

Solve the System of Equations x−y+5z=−43x+z=0−x+y−5z=12\begin{array} { r l r } x - y + 5 z & = & - 4 \\3 x + z & = & 0 \\- x + y - 5 z & = & 12\end{array}x−y+5z3x+z−x+y−5z​===​−4012​

Solve the System of Equations $\begin{array} { r l r } x - y + 5 z & = & - 4 \\3 x + z & = & 0 \\- x + y - 5 z & = & 12\end{array}$