Solve.
-$$\begin{aligned}
x + 3 y + 2 z & = 23 \
2 y + 3 z & = 23 \
z & = 5
\end{aligned}$$
$( 5,4,1 )$
A) No
B) Yes

Question

Quizplus · Accepted Answer

Substituting $z = 5$ into the second equation gives $2y + 3(5) = 23$, which simplifies to $2y + 15 = 23$, leading to $2y = 8$ and $y = 4$. Substituting $y = 4$ and $z = 5$ into the first equation gives $x + 3(4) + 2(5) = 23$, which simplifies to $x + 12 + 10 = 23$, leading to $x = 1$. Therefore, the solution $(x, y, z) = (1, 4, 5)$ is correct, making the answer "Yes."

Solve - x+3y+2z=232y+3z=23z=5\begin{aligned}x + 3 y + 2 z & = 23 \\2 y + 3 z & = 23 \\z & = 5\end{aligned}x+3y+2z2y+3zz​=23=23=5​

Solve
- $\begin{aligned}x + 3 y + 2 z & = 23 \\2 y + 3 z & = 23 \\z & = 5\end{aligned}$