Solve.
-$$\begin{array} { c }
x - y + 3 z = 6 \
5 x + z = 1 \
x + 2 y + z = - 5 \
( 0 , - 3,1 )
\end{array}$$
A) $\mathrm { No }$
B) Yes

Question

Solve.
-$$\begin{array} { c } 
x - y + 3 z = 6 \
5 x + z = 1 \
x + 2 y + z = - 5 \
( 0 , - 3,1 )
\end{array}$$
A) $\mathrm { No }$
B) Yes

Quizplus · Accepted Answer

To verify if the given solution $(0, -3, 1)$ satisfies all three equations, we substitute $x = 0$, $y = -3$, and $z = 1$ into each equation:1. $0 - (-3) + 3(1) = 3 + 3 = 6$, which matches the first equation.2. $5(0) + 1 = 1$, which matches the second equation.3. $0 + 2(-3) + 1 = -6 + 1 = -5$, which matches the third equation.Since the solution satisfies all three equations, it is correct.

Solve - x−y+3z=65x+z=1x+2y+z=−5(0,−3,1)\begin{array} { c } x - y + 3 z = 6 \\5 x + z = 1 \\x + 2 y + z = - 5 \\( 0 , - 3,1 )\end{array}x−y+3z=65x+z=1x+2y+z=−5(0,−3,1)​

Solve
- $\begin{array} { c } x - y + 3 z = 6 \\5 x + z = 1 \\x + 2 y + z = - 5 \\( 0 , - 3,1 )\end{array}$