Solve the problem.
-$2 a b ^ { 5 } \left( - 2 a b ^ { 7 } + 3 b ^ { 5 } - 4 a \right)$
A) $- 4 a b ^ { 7 } + 6 b ^ { 5 } - 8 a$
B) $- 4 a ^ { 2 } b ^ { 12 } + 6 a b ^ { 10 }$
C) $- 4 a ^ { 2 } b ^ { 12 } + 3 b ^ { 5 } - 4 a$
D) $- 4 a ^ { 2 } b ^ { 12 } + 6 a b ^ { 10 } - 8 a ^ { 2 } b ^ { 5 }$

Question

Quizplus · Accepted Answer

When multiplying terms, you add the exponents of like bases and multiply the coefficients. Applying this rule to each term inside the parentheses gives: $2ab^5(-2ab^7) = -4a^2b^{12}$, $2ab^5(3b^5) = 6ab^{10}$, and $2ab^5(-4a) = -8a^2b^5$. Combining these results gives the expression in choice D.

Solve the Problem 2ab5(−2ab7+3b5−4a)2 a b ^ { 5 } \left( - 2 a b ^ { 7 } + 3 b ^ { 5 } - 4 a \right)2ab5(−2ab7+3b5−4a)

Solve the Problem $2 a b ^ { 5 } \left( - 2 a b ^ { 7 } + 3 b ^ { 5 } - 4 a \right)$