Factor as completely as possible. If unfactorable, indicate that the polynomial is prime.
-$$27 a ^ { 2 } + 27 a - 12$$
A) $3 ( 3 a + 4 ) ( 3 a - 1 )$
B) $3 ( 3 a - 4 ) ( 3 a + 1 )$
C) $( 3 a + 4 ) ( 9 a - 3 )$
D) $( 9 a + 12 ) ( 3 a - 1 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is 3, to get $3(9a^2 + 9a - 4)$. Then, factor the trinomial inside the parentheses to get $3(3a + 4)(3a - 1)$.

Factor as Completely as Possible 27a2+27a−1227 a ^ { 2 } + 27 a - 1227a2+27a−12

Factor as Completely as Possible $27 a ^ { 2 } + 27 a - 12$