Factor using the trial and error method
-$20 y ^ { 2 } - 27 y + 9$
A) $( 4 y + 3 ) ( 5 y + 3 )$
B) $( 20 y + 3 ) ( y + 3 )$
C) $( 20 y - 3 ) ( y - 3 )$
D) $( 4 y - 3 ) ( 5 y - 3 )$

Question

Quizplus · Accepted Answer

The correct factorization is $(4y - 3)(5y - 3)$. Expanding this gives $20y^2 - 12y - 15y + 9 = 20y^2 - 27y + 9$, which matches the original expression.

Factor Using the Trial and Error Method - 20y2−27y+920 y ^ { 2 } - 27 y + 920y2−27y+9

Factor Using the Trial and Error Method
- $20 y ^ { 2 } - 27 y + 9$