Factor using the trial and error method
-$$10 y ^ { 2 } + 21 y + 9$$
A) $10 y ^ { 2 } + 21 y + 9$
B) $( 10 y + 3 ) ( y + 3 )$
C) $( 2 y + 3 ) ( 5 y + 3 )$
D) $( 2 y - 3 ) ( 5 y - 3 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by looking for two numbers that multiply to $10y^2 \times 9 = 90y^2$ and add to the middle term coefficient, 21y. The numbers 15y and 6y work, leading to the factorization $(2y + 3)(5y + 3)$.

Factor Using the Trial and Error Method - 10y2+21y+910 y ^ { 2 } + 21 y + 910y2+21y+9

Factor Using the Trial and Error Method
- $10 y ^ { 2 } + 21 y + 9$