Perform the operation indicated. Simplify.
-$$\frac { \frac { 7 } { x } + 1 } { \frac { 7 } { x } - 1 }$$
A) $7 - x ^ { 2 }$
B) $\frac { x ^ { 2 } } { 7 - x ^ { 2 } }$
C) $\frac { 7 + x } { 7 - x }$
D) 7

Question

Quizplus · Accepted Answer

To simplify the given expression, first, find a common denominator for the numerator and the denominator. The expression is $\frac { \frac { 7 } { x } + 1 } { \frac { 7 } { x } - 1 }$. To combine the fractions within the numerator and the denominator, convert 1 into a fraction that has $x$ as the denominator, which would be $\frac{x}{x}$. This gives us $\frac { \frac { 7 } { x } + \frac { x } { x } } { \frac { 7 } { x } - \frac { x } { x } }$, simplifying to $\frac { \frac { 7 + x } { x } } { \frac { 7 - x } { x } }$. Since the denominators in the numerator and denominator of the overall fraction are the same, they cancel out, leaving $\frac { 7 + x } { 7 - x }$.

Perform the Operation Indicated 7x+17x−1\frac { \frac { 7 } { x } + 1 } { \frac { 7 } { x } - 1 }x7​−1x7​+1​

Perform the Operation Indicated $\frac { \frac { 7 } { x } + 1 } { \frac { 7 } { x } - 1 }$