Solve the problem.
-When an object is dropped to the ground from a height of h meters, the time it takes for the object to reach the ground is given by the equation $t = \sqrt { \frac { \mathrm { h } } { 4.9 } }$, where $t$ is measured in seconds. Solve the equation for $h$. Use the result to determine the height from which an object was dropped if it hits the ground after falling for 5 seconds.
A) $h = 24.01 \mathrm { t } ^ { 2 } ; 600.3 \mathrm {~m}$
B) $\mathrm { h } = 24.01 \mathrm { t } ; 120.1 \mathrm {~m}$
C) $h = 4.9 t ^ { 2 } ; 122.5 \mathrm {~m}$
D) $\mathrm { h } = 4.9 \mathrm { t } ; 24.5 \mathrm {~m}$

Question

Quizplus · Accepted Answer

To solve for $h$, square both sides of the equation to get $t^2 = \frac{h}{4.9}$, then multiply both sides by 4.9 to isolate $h$, resulting in $h = 4.9t^2$. Substituting $t = 5$ seconds into the equation gives $h = 4.9 \times 5^2 = 4.9 \times 25 = 122.5$ meters.

Solve the Problem t=h4.9t = \sqrt { \frac { \mathrm { h } } { 4.9 } }t=4.9h​​

Solve the Problem $t = \sqrt { \frac { \mathrm { h } } { 4.9 } }$