Compute the discriminant. Then determine the number and type of solutions for the given equation.
-$$x ^ { 2 } + 2 x + 1 = 0$$
A) $- 4$; two complex imaginary solutions
B) 4 ; two unequal real solutions
C) 0 ; one real solution

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $D = b^2 - 4ac$. For the given equation $x^2 + 2x + 1 = 0$, $a = 1$, $b = 2$, and $c = 1$, so $D = 2^2 - 4(1)(1) = 4 - 4 = 0$. A discriminant of 0 indicates that there is exactly one real solution.

Compute the Discriminant x2+2x+1=0x ^ { 2 } + 2 x + 1 = 0x2+2x+1=0

Compute the Discriminant $x ^ { 2 } + 2 x + 1 = 0$