Solve the problem. -Write an equation in standard form of the parabola that has the same shape as the graph of f(x)=11 x² , but which has its vertex at (2,5) . A) $f ( x ) = 11 ( x + 2 ) ^ { 2 } + 5$ B) $f ( x ) = ( 11 x + 2 ) ^ { 2 } + 5$ C) $f ( x ) = 11 ( x - 2 ) ^ { 2 } + 5$ D) $f ( x ) = 11 ( x + 5 ) ^ { 2 } + 2$

Question

Quizplus · Accepted Answer

The correct equation is $f(x) = 11(x - 2)^2 + 5$ because the vertex form of a parabola is $f(x) = a(x - h)^2 + k$, where (h, k) is the vertex. Here, $a = 11$, $h = 2$, and $k = 5$, matching option C.

Solve the Problem f(x)=11(x+2)2+5f ( x ) = 11 ( x + 2 ) ^ { 2 } + 5f(x)=11(x+2)2+5

Solve the Problem $f ( x ) = 11 ( x + 2 ) ^ { 2 } + 5$