An op- amp has an open- loop gain of 90,000. Vsat = +/- 13 V. A differential voltage of 0.1 Vp- p is applied between the inputs. The output voltage is
A)26 Vp- p.
B)13 V.
C)- 13 V.
D)13 Vp- p.

Question

Quizplus · Accepted Answer

The output voltage of an op-amp is the product of its open-loop gain and the input differential voltage. Here, the open-loop gain is 90,000, and the input differential voltage is 0.1 Vp-p. Thus, the theoretical output voltage would be 90,000 * 0.1 V = 9,000 Vp-p. However, the op-amp is limited by its saturation voltage of +/- 13 V, meaning the maximum output it can provide is 13 V in either direction, making the peak-to-peak output 26 Vp-p.

An Op- Amp Has an Open- Loop Gain of 90,000