A self- biased n-channel JFET has a VD = 8 V, VGS = - 5 V. The value of VDS is
A)- 5 V.
B)- 3 V.
C)8 V.
D)3 V.

Question

Quizplus · Accepted Answer

VDS = VD - VS. Since VGS = -5 V and assuming VS = 0 (common for such problems), VD = 8 V, so VDS = 8 V - 0 V = 8 V. However, given VGS = -5 V, it implies a negative voltage is applied to the gate with respect to the source, which affects the calculation of VDS directly. The correct interpretation involves understanding that VDS = VD - VS, but with VGS given, it doesn't directly affect the calculation unless we're considering the impact on the source voltage, which isn't specified here. Thus, the direct calculation from the given VD leads to the realization that the initial explanation was incorrect in interpreting the role of VGS for this calculation. The correct approach is to recognize that VDS is the difference between the drain and source voltages directly, which in this case, without additional information about the source voltage, leads us to reconsider the direct relationship between VD and VDS in the context of the question's specifics. Given the misunderstanding, the correct calculation should focus on the direct relationship between the drain and source, leading to a reevaluation of the possible answers.

A Self- Biased N-Channel JFET Has a VD = 8