A voltage regulator is rated for an output range of IL = 0 to 40 mA. Under no-load conditions, the output voltage from the circuit is 4 Vdc. Under full-load conditions, the output voltage from the circuit is 3.984 Vdc. What is the load regulation rating of the circuit?
A) 400 μV/mA
B) 2.5 mV/mA
C) 0.4 Ω
D) Both 400 μV/mA and 0.4 Ω are correct.

Question

Quizplus · Accepted Answer

The load regulation rating can be calculated as the change in output voltage divided by the change in load current, which gives us the slope of the voltage change with respect to current. The change in voltage is 4 V - 3.984 V = 0.016 V or 16 mV. The change in current is 40 mA. So, the load regulation is 16 mV / 40 mA = 0.4 Ω, which can also be expressed as 400 μV/mA. Therefore, both 400 μV/mA and 0.4 Ω are correct descriptions of the load regulation.

A Voltage Regulator Is Rated for an Output Range of IL