-The circuit in Figure has the following values: RA=RB=10 kΩ and C=0.01 μF. What is the operating frequency of the circuit?
A) 7.2 kHz
B) 3.3 kHz
C) 4.8 kHz
D) 3.6 kHz

Question

-The circuit in Figure has the following values: RA=RB=10 kΩ and C=0.01 μF. What is the operating frequency of the circuit?
A) 7.2 kHz 
B) 3.3 kHz 
C) 4.8 kHz 
D) 3.6 kHz

Quizplus · Accepted Answer

The operating frequency of the circuit can be calculated using the formula for the frequency of a square wave oscillator, which is $f = \frac{1}{2.2RC}$, where R is the resistance and C is the capacitance. Given that $RA = RB = 10 k\Omega$ and $C = 0.01 \mu F$, the total resistance $R$ in the formula is $20 k\Omega$ (since $RA$ and $RB$ are in series for the purpose of calculating the frequency). Plugging the values into the formula gives $f = \frac{1}{2.2 \times 20,000 \times 0.01 \times 10^{-6}} = 4.545 kHz$, which rounds to approximately 4.8 kHz, making option C the closest answer.

-The Circuit in Figure Has the Following Values: RA=RB=10 KΩ