-The circuit in Figure has the following values: R1 = 7 kΩ, R2 = 1 kΩ, CB = 1 μF, and supply voltages of ±10 V. What is the value of Vref for this circuit?
A) +1.25 V
B) -1.25 V
C) + 2.5 V
D) -7.5 V

Question

-The circuit in Figure has the following values: R1 = 7 kΩ, R2 = 1 kΩ, CB = 1 μF, and supply voltages of ±10 V. What is the value of Vref for this circuit?
A) +1.25 V 
B) -1.25 V 
C) + 2.5 V 
D) -7.5 V

Quizplus · Accepted Answer

Vref is determined by the voltage divider formed by R1 and R2. The formula for the voltage at the junction of a voltage divider is Vout = Vin * (R2 / (R1 + R2)). Here, Vin = +10V (since we are looking for the positive reference voltage), R1 = 7kΩ, and R2 = 1kΩ. Plugging these values in gives Vout = 10V * (1kΩ / (7kΩ + 1kΩ)) = 10V * (1/8) = 1.25V.

-The Circuit in Figure Has the Following Values: R1 =