A CE amplifier is constructed using RC = 3.3 kΩ and RL = 12 kΩ. The transistor has the ~
Following specifications: hfe = 120, hie = 5 kΩ, hre = 4 × 10=4, and hoe = 2500 μS. What is the
Value for Av for this amplifier?
A) Approximately 62.2
B) Approximately 79.1
C) Approximately 287.8
D) None of the above.

Question

Quizplus · Accepted Answer

Av = -RL * hie * hfe / (hie + hre * RL) = -12k * 5k * 120 / (5k + 4e-4 * 12k) = -62.2

A CE Amplifier Is Constructed Using RC = 3