An emitter bias circuit has values of VCC = +8 V and VEE = -8 V. The value of VCEoff) for the circuit is
A) 4 V.
B) 8 V.
C) 16 V.
D) 0.7 V.

Question

Quizplus · Accepted Answer

VCE(off) is the collector-emitter voltage when the transistor is in the cutoff state, essentially when it is turned off. In an emitter bias circuit, VCE(off) is calculated by taking the difference between the supply voltages VCC and VEE, which in this case is +8 V - (-8 V) = 16 V.

An Emitter Bias Circuit Has Values of VCC = +8