The current through two identical light bulbs connected in series is 0.25 A. The voltage across both bulbs is 110 V. The resistance of a single light bulb is
A) 440 ohms.
B) 22 ohms.
C) 44 ohms.
D) 220 ohms.
E) none of these

Question

Quizplus · Accepted Answer

The total resistance in series is V/I = 110V / 0.25A = 440 ohms. Since the bulbs are identical and in series, each bulb has half of the total resistance: 440 ohms / 2 = 220 ohms.

The Current Through Two Identical Light Bulbs Connected in Series