The height of an object in feet above the ground is given in the following table.If heights of the object are cut in half, how does the average velocity change, over a given interval? $\begin{array}{cccccccc}
t \text { (sec) } & 0 & 1 & 2 & 3 & 4 & 5 & 6 \
y \text { (feet) } & 10 & 45 & 70 & 85 & 90 & 85 & 70
\end{array}$
A)It is cut in half.
B)It is doubled.
C)It remains the same.
D)It depends on the interval.

Question

Quizplus · Accepted Answer

If the heights are cut in half, the average velocity will also be cut in half.

The Height of an Object in Feet Above the Ground t (sec) 0123456y (feet) 10457085908570\begin{array}{cccccccc}t \text { (sec) } & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\y \text { (feet) } & 10 & 45 & 70 & 85 & 90 & 85 & 70\end{array}t (sec) y (feet) ​010​145​270​385​490​585​670​

The Height of an Object in Feet Above the Ground $\begin{array}{cccccccc}t \text { (sec) } & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\y \text { (feet) } & 10 & 45 & 70 & 85 & 90 & 85 & 70\end{array}$