The part of the graph of $\sin \left( x ^ { 2 } + y \right) = x$ that is near (0, $\pi$)defines y as a function of x implicitly.Does the graph of this function lie above or below its tangent line at (0, $\pi$)?

Question

The part of the graph of $\sin \left( x ^ { 2 } + y \right) = x$ that is near (0,  $\pi$)defines y as a function of x implicitly.Does the graph of this function lie above or below its tangent line at (0,  $\pi$)?

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The Answer of The part of the graph of $\sin \left( x ^ { 2 } + y \right) = x$ that is near (0,  $\pi$)defines y as a function of x implicitly.Does the graph of this function lie above or below its tangent line at (0,  $\pi$)?

The Part of the Graph Of sin⁡(x2+y)=x\sin \left( x ^ { 2 } + y \right) = xsin(x2+y)=x

The Part of the Graph Of $\sin \left( x ^ { 2 } + y \right) = x$