Differentiate $\frac { d } { d x } \left[ 7 e ^ { 2 x ^ { 2 } + 8 x } \right]$ .
A) $7 ( 4 x + 8 ) e ^ { 2 x ^ { 2 } + 8 x }$
B) $7 e ^ { 2 x ^ { 2 } + 8 x }$
C) $7 \ln \left( 2 x ^ { 2 } + 8 x \right) e ^ { 2 x ^ { 2 } + 8 x }$
D) $7 \left( 2 x ^ { 2 } + 8 x \right) e ^ { 2 x ^ { 2 } + 8 x - 1 }$

Question

Quizplus · Accepted Answer

The differentiation of $7e^{2x^2+8x}$ using the chain rule gives $7(4x+8)e^{2x^2+8x}$, where the derivative of the exponent $2x^2+8x$ is $4x+8$.

Differentiate ddx[7e2x2+8x]\frac { d } { d x } \left[ 7 e ^ { 2 x ^ { 2 } + 8 x } \right]dxd​[7e2x2+8x]

Differentiate $\frac { d } { d x } \left[ 7 e ^ { 2 x ^ { 2 } + 8 x } \right]$