A particle moves in such a way that $x ( t ) = 2 t ^ { 2 } + 8 \sin t$ .What is the instantaneous rate of change at t = 0?

Name: A particle moves in such a way that $x ( t ) = 2 t ^ { 2 } + 8 \sin t$ .What is the instantaneous rate of change at t = 0?
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The Answer of A particle moves in such a way that $x ( t ) = 2 t ^ { 2 } + 8 \sin t$ .What is the instantaneous rate of change at t = 0?

A Particle Moves in Such a Way That x(t)=2t2+8sin⁡tx ( t ) = 2 t ^ { 2 } + 8 \sin tx(t)=2t2+8sint

A Particle Moves in Such a Way That $x ( t ) = 2 t ^ { 2 } + 8 \sin t$