Given $f(x)=x^{3}-9 x^{2}+24 x-6$
, at which value(s)of x does the curve have a horizontal tangent?
A)1
B)2
C)3
D)4
E)5

Name: Given $f(x)=x^{3}-9 x^{2}+24 x-6$ , at which value(s)of x does the curve have a horizontal tangent? A)1 B)2 C)3 D)4 E)5
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Question

Given $f(x)=x^{3}-9 x^{2}+24 x-6$
 , at which value(s)of x does the curve have a horizontal tangent?
A)1
B)2
C)3
D)4
E)5

Quizplus · Accepted Answer

The curve has a horizontal tangent where the derivative $f'(x) = 3x^2 - 18x + 24$ is zero. Solving $3x^2 - 18x + 24 = 0$ gives $x = 2$ and $x = 4$.

Given f(x)=x3−9x2+24x−6f(x)=x^{3}-9 x^{2}+24 x-6f(x)=x3−9x2+24x−6 , at Which Value(s)of X Does the Curve Have a the Curve

Given $f(x)=x^{3}-9 x^{2}+24 x-6$ , at Which Value(s)of X Does the Curve Have a the Curve