A normal distribution in statistics is modeled by the function $N(x)=\frac{1}{\sqrt{2 \pi}} e^{-x^{2} / 2}$ determine where the maximum value of the function would occur. A)-2 B)-1 C)0 D)-2 $\pi$ E) $\ell$ ^-²

Question

Quizplus · Accepted Answer

The maximum value of the normal distribution function occurs at $x = 0$, because the exponent $-x^2 / 2$ reaches its maximum value (0) when $x = 0$, making the entire function maximum at this point.

A Normal Distribution in Statistics Is Modeled by the Function N(x)=12πe−x2/2N(x)=\frac{1}{\sqrt{2 \pi}} e^{-x^{2} / 2}N(x)=2π​1​e−x2/2

A Normal Distribution in Statistics Is Modeled by the Function $N(x)=\frac{1}{\sqrt{2 \pi}} e^{-x^{2} / 2}$