Suppose $\int_{a}^{b} g(x) d x=6$ , $\int_{a}^{b}(g(x))^{2} d x=8$ , $\int_{a}^{b} h(x) d x=0$ , and $\int_{a}^{b}(h(x))^{2} d x=2$ .Find $\int_{a}^{b}\left((g(x))^{2}+(h(x))^{2}\right) d x$ .

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The Answer of Suppose $\int_{a}^{b} g(x) d x=6$ , $\int_{a}^{b}(g(x))^{2} d x=8$ , $\int_{a}^{b} h(x) d x=0$ , and $\int_{a}^{b}(h(x))^{2} d x=2$ .Find $\int_{a}^{b}\left((g(x))^{2}+(h(x))^{2}\right) d x$ .

Suppose ∫abg(x)dx=6\int_{a}^{b} g(x) d x=6∫ab​g(x)dx=6 ∫ab(g(x))2dx=8\int_{a}^{b}(g(x))^{2} d x=8∫ab​(g(x))2dx=8 ∫abh(x)dx=0\int_{a}^{b} h(x) d x=0∫ab​h(x)dx=0

Suppose $\int_{a}^{b} g(x) d x=6$ $\int_{a}^{b}(g(x))^{2} d x=8$ $\int_{a}^{b} h(x) d x=0$