Find the general antiderivative of $P(x)=\frac{1}{2 x}$ .
A) $2 \ln |x|+C$
B) $\frac{1}{2} \ln |x|+C$
C) $\frac{-2}{2} x^{-2}+C$
D) $-(2 x)^{-2}+C$
E) $\ln |2 x|+C$

Question

Quizplus · Accepted Answer

The antiderivative of $P(x) = \frac{1}{2x}$ is $\frac{1}{2} \ln |x| + C$ because the integral of $1/x$ is $\ln|x|$, and the constant $1/2$ is factored out of the integral.

Find the General Antiderivative Of P(x)=12xP(x)=\frac{1}{2 x}P(x)=2x1​ A) 2ln⁡∣x∣+C2 \ln |x|+C2ln∣x∣+C

Find the General Antiderivative Of $P(x)=\frac{1}{2 x}$
A) $2 \ln |x|+C$