Find an antiderivative of $\cos (7 \theta)$ .
A) $7 \sin (7 \theta)+C$
B) $-7 \sin (7 \theta)+C$
C) $\frac{1}{7} \sin (7 \theta)+C$
D) $-\frac{1}{7} \sin (7 \theta)+C$

Question

Quizplus · Accepted Answer

The antiderivative of $\cos(7\theta)$ is $\frac{1}{7}\sin(7\theta)+C$ because when differentiating $\sin(7\theta)$, the chain rule is applied, resulting in $7\cos(7\theta)$, thus to reverse this, we integrate and divide by 7.

Find an Antiderivative Of cos⁡(7θ)\cos (7 \theta)cos(7θ) A) 7sin⁡(7θ)+C7 \sin (7 \theta)+C7sin(7θ)+C

Find an Antiderivative Of $\cos (7 \theta)$
A) $7 \sin (7 \theta)+C$