$\int \frac{1}{6 x+4} d x=\frac{1}{6} \ln |6 x+4|+C$ .

Name: $\int \frac{1}{6 x+4} d x=\frac{1}{6} \ln |6 x+4|+C$ .
Brand: Quizplus
Rating: 4.8 (39 reviews)

Question

Quizplus · Accepted Answer

The integral $\int \frac{1}{6x+4} dx$ can be solved by using the substitution method or recognizing it as a standard form. The derivative of $6x+4$ is $6$, which matches the constant in the denominator after adjusting for the constant multiple. Thus, integrating gives $\frac{1}{6}\ln|6x+4| + C$.

∫16x+4dx=16ln⁡∣6x+4∣+C\int \frac{1}{6 x+4} d x=\frac{1}{6} \ln |6 x+4|+C∫6x+41​dx=61​ln∣6x+4∣+C

$\int \frac{1}{6 x+4} d x=\frac{1}{6} \ln |6 x+4|+C$