$\int(1+x) \sin (4 x) d x=-\frac{\cos 4 x}{4}+\frac{x \cos 4 x}{4}-\frac{\sin 4 x}{16}+C$

$\int(1+x) \sin (4 x) d x=-\frac{\cos 4 x}{4}+\frac{x \cos 4 x}{4}-\frac{\sin 4 x}{16}+C$ .