Use the table of antiderivatives to determine if the following statement is true. $\int \frac{d t}{\sqrt{4-7 t^{2}}}=\frac{1}{7} \arcsin \left(\frac{t \sqrt{7}}{2}\right)+C$

Name: Use the table of antiderivatives to determine if the following statement is true. $\int \frac{d t}{\sqrt{4-7 t^{2}}}=\frac{1}{7} \arcsin \left(\frac{t \sqrt{7}}{2}\right)+C$
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Quizplus · Accepted Answer

The correct antiderivative should be $\frac{1}{\sqrt{7}} \arcsin \left(\frac{t \sqrt{7}}{2}\right)+C$, not $\frac{1}{7}$.

Use the Table of Antiderivatives to Determine If the Following ∫dt4−7t2=17arcsin⁡(t72)+C\int \frac{d t}{\sqrt{4-7 t^{2}}}=\frac{1}{7} \arcsin \left(\frac{t \sqrt{7}}{2}\right)+C∫4−7t2​dt​=71​arcsin(2t7​​)+C

Use the Table of Antiderivatives to Determine If the Following $\int \frac{d t}{\sqrt{4-7 t^{2}}}=\frac{1}{7} \arcsin \left(\frac{t \sqrt{7}}{2}\right)+C$