Calculate $\int \sec ^{2} \theta d \theta$
A) $\frac{3 \sin \theta}{\cos ^{3} \theta}+C$
B) $-\frac{1}{\cos \theta}+C$
C) $\tan \theta+C$
D) $\tan ^{2} \theta+C$

Name: Calculate $\int \sec ^{2} \theta d \theta$ A) $\frac{3 \sin \theta}{\cos ^{3} \theta}+C$ B) $-\frac{1}{\cos \theta}+C$ C) $\tan \theta+C$ D) $\tan ^{2} \theta+C$
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Question

Quizplus · Accepted Answer

The integral of $\sec^2 \theta$ with respect to $\theta$ is $\tan \theta + C$, which is a standard result in calculus.

Calculate ∫sec⁡2θdθ\int \sec ^{2} \theta d \theta∫sec2θdθ A) 3sin⁡θcos⁡3θ+C\frac{3 \sin \theta}{\cos ^{3} \theta}+Ccos3θ3sinθ​+C

Calculate $\int \sec ^{2} \theta d \theta$ A) $\frac{3 \sin \theta}{\cos ^{3} \theta}+C$