The acceleration of a moving object is given by $\frac{d^{2} x}{d t^{2}}=x\left(\frac{d x}{d t}-1\right)$ where x(t)is the position at time t.Use a graphing calculator to help sketch the slope field and the trajectory for the initial values x(0)= -3, v(0)= 3.Approximate the maximum value of x to the nearest integer.If the maximum does not exist, enter "DNE".

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The Answer of The acceleration of a moving object is given by $\frac{d^{2} x}{d t^{2}}=x\left(\frac{d x}{d t}-1\right)$ where x(t)is the position at time t.Use a graphing calculator to help sketch the slope field and the trajectory for the initial values x(0)= -3, v(0)= 3.Approximate the maximum value of x to the nearest integer.If the maximum does not exist, enter "DNE".

The Acceleration of a Moving Object Is Given By d2xdt2=x(dxdt−1)\frac{d^{2} x}{d t^{2}}=x\left(\frac{d x}{d t}-1\right)dt2d2x​=x(dtdx​−1)

The Acceleration of a Moving Object Is Given By $\frac{d^{2} x}{d t^{2}}=x\left(\frac{d x}{d t}-1\right)$