The temperature at each point in the first quadrant is given by $T ( x , y ) = \ln ( x y ) - \frac { x } { 6 } - \frac { y } { 5 }$ .Find the hottest point in the first quadrant and determine its temperature.

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The Answer of The temperature at each point in the first quadrant is given by $T ( x , y ) = \ln ( x y ) - \frac { x } { 6 } - \frac { y } { 5 }$ .Find the hottest point in the first quadrant and determine its temperature.

The Temperature at Each Point in the First Quadrant Is T(x,y)=ln⁡(xy)−x6−y5T ( x , y ) = \ln ( x y ) - \frac { x } { 6 } - \frac { y } { 5 }T(x,y)=ln(xy)−6x​−5y​

The Temperature at Each Point in the First Quadrant Is $T ( x , y ) = \ln ( x y ) - \frac { x } { 6 } - \frac { y } { 5 }$