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Let F=xj\vec { F } = x \vec { j }

Question 51

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Let F=xj\vec { F } = x \vec { j } Let C1 be the line from (0, 0)to (2, 0), C2 the line from (2, 0)to (2,-1), C3 the line from (2,-1)to (0,-1), and C4 the line from (0,-1)to (0, 0).
(A)Using the definition of line integral only, without parameterizing the curves, show that the line integral of F\vec{F} along C = C1 + C2 + C3 + C4 is -2.That is, show CFdr=2\int_{C} \vec{F} \cdot \overline{d r}=-2 (B)The rectangle, R, enclosed by the lines C1, C2, C3 and C4 is of area 2.So, by Green's Theorem CFdr=R(xx0)dA= Area of R=2\int _ { C } \vec { F } \cdot \overline { d r } = \int _ { R } \left( \frac { \partial x } { \partial x } - 0 \right) d A = \text { Area of } R = 2 Is something wrong?

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(A)Along paths C1 and C3, the vector field...

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