Suppose that $\int_{c} \vec{F} \cdot d \vec{r}=6$ , where C is the circle of radius 1, centered at the origin, starting at (1, 0)and traveling counter-clockwise back to (1, 0).$\int _ { G _ { 1 } } 2 \vec { F } \cdot d \vec { r } = 12$

Question

Quizplus · Accepted Answer

The second integral is twice the first integral, which is consistent with the given values: $2 \times 6 = 12$.

Suppose That ∫cF⃗⋅dr⃗=6\int_{c} \vec{F} \cdot d \vec{r}=6∫c​F⋅dr=6 , Where C Is the Circle of Radius 1, Centered

Suppose That $\int_{c} \vec{F} \cdot d \vec{r}=6$ , Where C Is the Circle of Radius 1, Centered