What is the flux of the vector field $\overrightarrow { \vec { F } } = - 5 \vec { i } + 6 \vec { j } + 2 \vec { k }$ through a circle in the xy-plane of radius 2 oriented upward with center at the origin?

Name: What is the flux of the vector field $\overrightarrow { \vec { F } } = - 5 \vec { i } + 6 \vec { j } + 2 \vec { k }$ through a circle in the xy-plane of radius 2 oriented upward with center at the origin?
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The Answer is

8 \pi

What Is the Flux of the Vector Field F⃗→=−5i⃗+6j⃗+2k⃗\overrightarrow { \vec { F } } = - 5 \vec { i } + 6 \vec { j } + 2 \vec { k }F=−5i+6j​+2k

What Is the Flux of the Vector Field $\overrightarrow { \vec { F } } = - 5 \vec { i } + 6 \vec { j } + 2 \vec { k }$