Calculate the solubility of lead(II) iodide, PbI₂, in 0.025 M KI. K_sp = 7.9 *10¯⁹ A) 4.5 *10¯² M B) 2.8 * 10¯² M C) 8.9 * 10¯⁵ M D) 5.0 * 10¯⁵ M E) 1.3 * 10¯⁵ M

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The solubility of PbI2 in a solution containing a common ion (I-) is calculated using the Ksp expression: Ksp = [Pb2+][I-]^2. In 0.025 M KI, [I-] is approximately 0.025 M. Solving for [Pb2+] gives a solubility of approximately 1.3 * 10^-5 M.

Calculate the Solubility of Lead(II) Iodide, PbI2, in 0

Calculate the Solubility of Lead(II) Iodide, PbI₂, in 0