According to Valence Bond theory, in the square planar Ni(CN)₄²¯ complex ion, the orbital hybridization pattern is: A) sp³ B) dsp² C) d²sp D) d²sp³ E) None of these choices is correct.

Question

Quizplus · Accepted Answer

In the square planar Ni(CN)₄²⁻ complex, nickel is in a +2 oxidation state, and the hybridization is dsp², involving one d, one s, and two p orbitals.

According to Valence Bond Theory, in the Square Planar Ni(CN)42¯

According to Valence Bond Theory, in the Square Planar Ni(CN)₄²¯