How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO₃ (? = 84.02 g/mol) ?
HCl(aq) + NaHCO₃(s) $\rightarrow$ NaCl(s) + H₂O(l) + CO₂(g)

Question

How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO₃ (? = 84.02 g/mol) ?
HCl(aq) + NaHCO₃(s)

\rightarrow

NaCl(s) + H₂O(l) + CO₂(g)

Quizplus · Accepted Answer

The Answer of How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO₃ (? = 84.02 g/mol)? HCl(aq) + NaHCO₃(s) $\rightarrow$ NaCl(s) + H₂O(l) + CO₂(g) A) 638 mL B) 572 mL C) 536 mL D) 276 mL E) 175 mL

How Many Milliliters of 1 →\rightarrow→ NaCl(s) + H2O(l) + CO2(g) A) 638 ML B) 572

How Many Milliliters of 1 $\rightarrow$ NaCl(s) + H₂O(l) + CO₂(g)
A) 638 ML
B) 572