Sodium chlorate is used as an oxidizer in the manufacture of dyes, explosives, and matches. Calculate the mass of solute needed to prepare 1.575 L of 0.00250 M NaClO₃(ℳ = 106.45 g/mol). A)419 g B)169 g C)0.419 g D)0.169 g E)0.00394 g

Question

Quizplus · Accepted Answer

We can use the formula:

mass = moles x molar mass

First, we need to calculate the number of moles of NaClO3:

moles = Molarity x Volume
moles = 0.00250 mol/L x 1.575 L
moles = 0.00394 mol

Then, we can calculate the mass:

mass = moles x molar mass
mass = 0.00394 mol x 106.45 g/mol
mass = 0.419 g

Therefore, the answer is choice C, 0.419 g.

Sodium Chlorate Is Used as an Oxidizer in the Manufacture