Given that Z is a standard normal variable, the value z for which P(Z $\leq$ z) = 0.6736 is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.1736 . \
\hline \text { B. } & 0.45 . \
\hline \text { C. } & -0.1736 . \
\hline \text { D. } & -0.45 . \
\hline
\end{array}$

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The Answer of Given that Z is a standard normal variable, the value z for which P(Z $\leq$ z) = 0.6736 is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.1736 . \
\hline \text { B. } & 0.45 . \
\hline \text { C. } & -0.1736 . \
\hline \text { D. } & -0.45 . \
\hline
\end{array}$

Given That Z Is a Standard Normal Variable, the Value ≤\leq≤

Given That Z Is a Standard Normal Variable, the Value $\leq$