If $S S _ { \text {Total } } = 150.00 , S S _ { A } = 8.00 , S S _ { B } = 10.00 , S S _ { A } \times B = 12.00 , S S _ { \text {Error } } = 120.00 , d f _ { \text {Total } } = 65$, $d f _ { A } = 2 , d f _ { B } = 1 , d f _ {{ A } \times B} = 2$, and $d f _ { \text {Error } } = 60$ in a two-factor between-subjects analysis of variance, then $M S _ { B } =$ and $M S _ { A \times B } =$
A)6.00; 10.00
B)10.00; 80.00
C)5.00; 12.00
D)10.00; 6.00

Question

Quizplus · Accepted Answer

Mean Square (MS) is calculated by dividing the sum of squares (SS) by the degrees of freedom (df). Therefore, $MS_B = \frac{SS_B}{df_B} = \frac{10.00}{1} = 10.00$ and $MS_{A \times B} = \frac{SS_{A \times B}}{df_{A \times B}} = \frac{12.00}{2} = 6.00$.

If dfA=2,dfB=1,dfA×B=2d f _ { A } = 2 , d f _ { B } = 1 , d f _ {{ A } \times B} = 2dfA​=2,dfB​=1,dfA×B​=2

If $d f _ { A } = 2 , d f _ { B } = 1 , d f _ {{ A } \times B} = 2$