If $S S _ { \text {Total } } = 150.00 , S S _ { A } = 8.00 , S S _ { B } = 10.00 , S S _ { A } \times B = 12.00 , S S _ { \text {Error } } = 120.00 , d f$ Total $= 65$, $d f _ { A } = 2 , d f _ { B } = 1 , d f _ {{ A } \times B} = 2$, and $d f _ { \text {Error } } = 60$ in a two-factor between-subjects analysis of variance, then $M S _ { A } = \ldots$ and $M S _ { \text {Error } } =$
A)4.00; 6.00
B)4.00; 2.00
C)16.00; 7200.00
D)8.00; 30.00

Question

Quizplus · Accepted Answer

Mean Square (MS) is calculated by dividing the sum of squares (SS) by the degrees of freedom (df). For factor A, $MS_A = \frac{SS_A}{df_A} = \frac{8.00}{2} = 4.00$. For error, $MS_{Error} = \frac{SS_{Error}}{df_{Error}} = \frac{120.00}{60} = 2.00$.

If SSTotal =150.00,SSA=8.00,SSB=10.00,SSA×B=12.00,SSError =120.00,dfS S _ { \text {Total } } = 150.00 , S S _ { A } = 8.00 , S S _ { B } = 10.00 , S S _ { A } \times B = 12.00 , S S _ { \text {Error } } = 120.00 , d fSSTotal ​=150.00,SSA​=8.00,SSB​=10.00,SSA​×B=12.00,SSError ​=120.00,df

If $S S _ { \text {Total } } = 150.00 , S S _ { A } = 8.00 , S S _ { B } = 10.00 , S S _ { A } \times B = 12.00 , S S _ { \text {Error } } = 120.00 , d f$