In a two-sample test for differences in means, the hypotheses are of the form: A) $ H_{0}: \mu_{1}-\mu_{2}\{\geq, \leq $, or $ =\} 0 $ $ H_{1}: \mu_{1}-\mu_{2}\{,,_{1},

Question

In a two-sample test for differences in means, the hypotheses are of the form: A) $ H_{0}: \mu_{1}-\mu_{2}\{\geq, \leq $, or $ =\} 0 $ $ H_{1}: \mu_{1}-\mu_{2}\{>,< $, or $ =\} 0 $ B) $ H_{0}: \mu_{1}-\mu_{2}\{\geq, \leq $, or $ =\} 0 $ $ H_{1}: \mu_{1}-\mu_{2}\{>,< $, or $ \neq\} 0 $ C) $ H_{0}: \mu 1-\mu 2\{\geq, \leq $, or $ \neq\} 0 $ $ H_{1}: \mu_{1}-\mu_{2}\left\{>_{1}<\right. $, or $ \left.=\right\} 0 $ D) $ H_{0}: \mu 1-\mu 2\{>,< $, or $ =\} 0 $ $ H_{1}: \mu 1-\mu 2\{\leq, \geq $, or $ \neq\} 0 $

Quizplus · Accepted Answer

The correct form of hypothesis in a two-sample test for differences in means is $ H_{0}: \mu_{1}-\mu_{2}= 0 $ and $ H_{1}: \mu_{1}-\mu_{2}\neq 0 $ or $ H_{1}: \mu_{1}- \mu_{2}>0 $ or $ H_{1}: \mu_{1} -\mu_{2} < 0 $. Option B correctly represents these hypotheses by allowing for a two-sided test ($ \neq $ in $ H_{1} $) and either directionality in the alternative hypothesis ($ > $ or $<$ in $ H_{1} $).

In a Two-Sample Test for Differences in Means, the Hypotheses H0:μ1−μ2{≥,≤ H_{0}: \mu_{1}-\mu_{2}\{\geq, \leq H0​:μ1​−μ2​{≥,≤

In a Two-Sample Test for Differences in Means, the Hypotheses $H_{0}: \mu_{1}-\mu_{2}\{\geq, \leq$