A baseball is thrown with a velocity at an angle $\theta$ with the horizontal. The horizontal component of its velocity in the absence of air resistance is A) v cos $\theta$ B) v cos $\theta$ - gt. C) v² + 2gx. D) v² - 2gx. E) v sin $\theta$ - gt.

Question

Quizplus · Accepted Answer

The horizontal component of velocity is given by v cosθ, where θ is the angle of the velocity vector with the horizontal. In this case, the angle is given as θ= F1F1F1S1θF1F1F10. Therefore, the horizontal component of velocity is v cos( F1F1F1S1θF1F1F10) which corresponds to choice A.

A Baseball Is Thrown with a Velocity at an Angle